1894. 找到需要补充粉笔的学生编号 发表于 2021-12-17 更新于 2022-10-29 分类于 leecode刷题复习 这是文章开头,显示在主页面,详情请点击此处。 12345678class Solution: def chalkReplacer(self, chalk: List[int], k: int) -> int: sum_chalk = sum(chalk) remainder = k%sum_chalk for i in range(len(chalk)): remainder -= chalk[i] if remainder < 0: return i